1. The problem asks to locate the point $(-1.6, -1)$ on the Cartesian coordinate plane and identify its position relative to the axes or quadrants. 2. Recall that the Cartesian plane is divided into four quadrants: - Quadrant I: $x > 0$, $y > 0$ - Quadrant II: $x < 0$, $y > 0$ - Quadrant III: $x < 0$, $y < 0$ - Quadrant IV: $x > 0$, $y < 0$ 3. The point given is $(-1.6, -1)$, where $x = -1.6$ and $y = -1$. 4. Since both $x$ and $y$ are negative, the point lies in Quadrant III. 5. The point is not on either axis because neither coordinate is zero. Final answer: The point $(-1.6, -1)$ is located in the third quadrant of the Cartesian coordinate plane.