1. The problem asks if the point $(-5,0)$ lies on circle $Q$ centered at the origin $(0,0)$ with radius 5. 2. The formula for a circle centered at the origin is $$x^2 + y^2 = r^2$$ where $r$ is the radius. 3. Here, $r = 5$, so the equation is $$x^2 + y^2 = 5^2 = 25$$. 4. To check if $(-5,0)$ is on the circle, substitute $x = -5$ and $y = 0$ into the equation: $$(-5)^2 + 0^2 = 25 + 0 = 25$$. 5. Since the left side equals the right side ($25 = 25$), the point satisfies the circle's equation. 6. Therefore, the distance from the origin to $(-5,0)$ is equal to the radius, so the point lies on the circle. Final answer: Yes because the distance from the origin to point $(-5, 0)$ is equal to the radius of the circle.