1. Problem: Find the image of point A(-10,5) under the translation vector T = (2,6). 2. Formula: Translation of a point $(x,y)$ by vector $T = (a,b)$ results in a new point $(x',y')$ where: $$x' = x + a$$ $$y' = y + b$$ 3. Apply the formula: $$x' = -10 + 2 = -8$$ $$y' = 5 + 6 = 11$$ 4. So, the image of point A is $(-8,11)$. 5. Check the options: None exactly match $(-8,11)$, but the closest is option B with a typo (-8’13). Assuming a typo, the correct answer is B. Final answer: B. (-8,13) (assuming typo in question)