1. **State the problem:** Find the area of a polygon with sides meeting at right angles and given side lengths. 2. **Approach:** Since the polygon is rectilinear (all angles are right angles), we can divide it into rectangles and sum their areas. 3. **Identify segments:** - Bottom side: 13 in - Left vertical side: 6 in - Top left horizontal: 4 in - Vertical drop: 2 in - Middle horizontal: 5 in - Vertical rise: 2 in - Top right horizontal: 4 in - Right vertical side: 6 in 4. **Divide polygon into rectangles:** - Rectangle A (left bottom): width 4 in, height 6 in - Rectangle B (middle bottom): width 5 in, height 2 in - Rectangle C (right bottom): width 4 in, height 6 in 5. **Calculate areas:** - Area A = $4 \times 6 = 24$ - Area B = $5 \times 2 = 10$ - Area C = $4 \times 6 = 24$ 6. **Sum areas:** $$\text{Total area} = 24 + 10 + 24 = 58$$ 7. **Final answer:** The area of the figure is **58 square inches**.