1. **State the problem:** We need to find the area of an irregular polygon with given side lengths.
2. **Approach:** We can divide the polygon into simpler shapes (rectangles and triangles), calculate their areas, and sum them.
3. **Divide the figure:**
- The polygon can be split into two rectangles and one right triangle.
4. **Calculate areas:**
- Rectangle 1 (top left): width = 7 km, height = 4 km
$$\text{Area}_1 = 7 \times 4 = 28$$ km²
- Rectangle 2 (middle right): width = 4 km, height = 3 km
$$\text{Area}_2 = 4 \times 3 = 12$$ km²
- Triangle (bottom right): base = 6 km, height = 2 km
$$\text{Area}_3 = \frac{1}{2} \times 6 \times 2 = 6$$ km²
5. **Sum all areas:**
$$\text{Total Area} = 28 + 12 + 6 = 46$$ km²
6. **Answer:** The area of the figure is **46 km²**.
Polygon Area 7D7E62
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.