1. **State the problem:** Calculate the area of an irregular polygon with given side lengths in inches. 2. **Approach:** We can find the area by decomposing the polygon into rectangles and summing their areas. 3. **Identify rectangles:** - Rectangle A: width 3 in (top left horizontal segment), height 16 in (left vertical side) - Rectangle B: width 3 in (middle horizontal segment), height 7 in (vertical segment down from 4 in to 11 in) - Rectangle C: width 9 in (bottom horizontal segment), height 5 in (vertical segment down from 11 in to 16 in) 4. **Calculate areas:** - Area A = $3 \times 16 = 48$ square inches - Area B = $3 \times 7 = 21$ square inches - Area C = $9 \times 5 = 45$ square inches 5. **Sum areas:** $$\text{Total area} = 48 + 21 + 45 = 114$$ square inches 6. **Final answer:** The area of the irregular polygon is **114 square inches**.