1. **Problem Statement:** Find the area of the irregular polygon with given side lengths: vertical left side 17 yd, horizontal segments 5 yd, 4 yd, 5 yd, 5 yd, bottom base 7 yd, vertical segment 9 yd, and large horizontal base 15 yd. 2. **Approach:** We can divide the irregular polygon into rectangles and squares, calculate each area, then sum them. 3. **Step 1: Break down the figure vertically:** - The total height on the left is 17 yd. - The vertical segment on the right is 9 yd. - The difference in height between left and right sides is $17 - 9 = 8$ yd. 4. **Step 2: Break down horizontally:** - The bottom base is 7 yd. - The large horizontal base on the right is 15 yd. - The horizontal segments on the left side add up to $5 + 4 + 5 + 5 = 19$ yd. 5. **Step 3: Identify rectangles:** - Rectangle A (left vertical strip): width 5 yd, height 17 yd, area $5 \times 17 = 85$ yd$^2$. - Rectangle B (middle horizontal strip): width 4 yd, height 8 yd (difference in height), area $4 \times 8 = 32$ yd$^2$. - Rectangle C (bottom right rectangle): width 15 yd, height 9 yd, area $15 \times 9 = 135$ yd$^2$. 6. **Step 4: Sum areas:** $$\text{Total area} = 85 + 32 + 135 = 252 \text{ yd}^2$$ 7. **Answer:** The area of the irregular polygon is $252$ square yards.