1. **Stating the problem:**
Calculate the area of the irregular polygon described, which resembles a trapezoid with a rectangular notch cut out from the bottom-left interior.
2. **Formula and approach:**
The area of an irregular polygon can be found by decomposing it into simpler shapes (rectangles, trapezoids) and subtracting the area of the notch.
3. **Identify dimensions:**
- The left side height is 15 units.
- The right side height is 9 units.
- The bottom side is divided into two parts: 3 units (notch width) and 10 units (main base).
- The notch height is 4 units.
- The top side length is 8 units.
4. **Calculate the area of the main trapezoid:**
The trapezoid has parallel sides of lengths 15 (left height) and 9 (right height), and a base length of 13 (3 + 10).
Area of trapezoid = $$\frac{(a+b)}{2} \times h = \frac{(15+9)}{2} \times 13 = \frac{24}{2} \times 13 = 12 \times 13 = 156$$
5. **Calculate the area of the rectangular notch:**
Area of notch = width \times height = 3 \times 4 = 12
6. **Calculate the area of the irregular polygon:**
Area = Area of trapezoid - Area of notch = 156 - 12 = 144
**Final answer:**
$$\boxed{144}$$
Polygon Area D4B06A
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.