1. **Problem Statement:** Calculate the volume of water in a pool with given dimensions where water is filled to 9 feet from the top. 2. **Given Dimensions:** - a = 4 ft (small height segment) - b = 12 ft (width) - h = 10 ft (height) - x = 20 ft (length front) - y = 54 ft (length middle) - z = 20 ft (length back) 3. **Water Level:** Water is filled to 9 ft from the top, so water depth = total height - 9 ft = $10 - 9 = 1$ ft. 4. **Understanding the Shape:** The pool is a trapezoidal prism with varying lengths along the base (x, y, z) and a height h. 5. **Volume Calculation:** Volume of water = area of water surface × water depth. 6. **Calculate the average length of the pool base:** $$\text{Average length} = \frac{x + y + z}{3} = \frac{20 + 54 + 20}{3} = \frac{94}{3} \approx 31.33 \text{ ft}$$ 7. **Calculate the area of the water surface:** $$\text{Area} = b \times \text{Average length} = 12 \times 31.33 = 375.96 \text{ ft}^2$$ 8. **Calculate the volume of water:** $$\text{Volume} = \text{Area} \times \text{Water depth} = 375.96 \times 1 = 375.96 \text{ ft}^3$$ **Final Answer:** The volume of water in the pool is approximately **375.96 ft³**.