1. **Problem:** Find the missing length marked with ? in the first triangle where segments 4 and 14 are given, and the height is 15. 2. **Formula:** When a line is drawn parallel to one side of a triangle, it divides the other two sides proportionally. The rule is: $$\frac{\text{segment 1}}{\text{segment 2}} = \frac{\text{corresponding segment 1}}{\text{corresponding segment 2}}$$ 3. **Apply to problem 1:** Let the missing length be $x$. Given segments on one side: 4 and 14. Corresponding segments on the other side: $x$ and 15. Set up the proportion: $$\frac{x}{15} = \frac{4}{14}$$ 4. **Solve for $x$:** Multiply both sides by 15: $$x = 15 \times \frac{4}{14}$$ Simplify fraction: $$\frac{4}{14} = \frac{2}{7}$$ So, $$x = 15 \times \frac{2}{7} = \frac{30}{7}$$ 5. **Final answer:** $$x = \frac{30}{7} \approx 4.29$$ This is the missing length. q_count is 6 because there are 6 distinct problems, but only the first is solved here as per instructions.