1. **State the problem:** Find the surface area of a pyramid with a square base where each side of the base measures 11 meters and the slant height of the triangular faces is 16 meters. 2. **Formula for surface area of a pyramid with a square base:** $$\text{Surface Area} = \text{Base Area} + \text{Lateral Area}$$ where $$\text{Base Area} = s^2$$ and $$\text{Lateral Area} = \frac{1}{2} \times \text{Perimeter of base} \times \text{Slant height}$$ 3. **Calculate the base area:** $$s = 11$$ $$\text{Base Area} = 11^2 = 121$$ 4. **Calculate the perimeter of the base:** $$\text{Perimeter} = 4 \times 11 = 44$$ 5. **Calculate the lateral area:** $$\text{Lateral Area} = \frac{1}{2} \times 44 \times 16$$ $$= 22 \times 16 = 352$$ 6. **Calculate the total surface area:** $$\text{Surface Area} = 121 + 352 = 473$$ 7. **Answer:** The surface area of the pyramid is **473** square meters.