Subjects geometry

Pythagorean Theorem A4Cf4C

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1. The problem states the Pythagorean Theorem: $$a^2 + b^2 = c^2$$ and gives values $a=7$ and $b=11$. We need to find $c^2$. 2. First, calculate $a^2$ and $b^2$: $$a^2 = 7^2 = 7 \times 7 = 49$$ $$b^2 = 11^2 = 11 \times 11 = 121$$ 3. Now, add $a^2$ and $b^2$ to find $c^2$: $$c^2 = a^2 + b^2 = 49 + 121 = 170$$ 4. Therefore, $c^2$ equals 170. The correct answer is A. 170.