1. **Problem:** Given a right-angled triangle PQR with right angle at R, hypotenuse PQ = 16 cm, and leg PR = 8 cm, find the length of QR to 2 decimal places. 2. **Formula:** Use Pythagorean theorem: $$PQ^2 = PR^2 + QR^2$$ 3. **Step 1:** Substitute known values: $$16^2 = 8^2 + QR^2$$ 4. **Step 2:** Calculate squares: $$256 = 64 + QR^2$$ 5. **Step 3:** Isolate $QR^2$: $$QR^2 = 256 - 64$$ 6. **Step 4:** Simplify: $$QR^2 = 192$$ 7. **Step 5:** Find $QR$ by taking the square root: $$QR = \sqrt{192}$$ 8. **Step 6:** Calculate the square root: $$QR \approx 13.8564$$ 9. **Step 7:** Round to 2 decimal places: $$QR \approx 13.86$$ **Final answer:** The length of QR is approximately 13.86 cm.