Subjects geometry

Quadrilateral Angles 3A7D71

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1. **Problem Statement:** Find the missing angle measures $m\angle 1$, $m\angle 2$, and $m\angle 3$ for problems 5 and 6 in the quadrilaterals. 2. **Important Rule:** The sum of interior angles in any quadrilateral is always $$360^\circ$$. --- ### Problem 5: Given angles: 61, 88, 120, 76 degrees. Step 1: Sum the known angles: $$61 + 88 + 120 + 76 = 345$$ Step 2: Since the total must be 360, the missing angle is: $$360 - 345 = 15$$ Step 3: Assign the missing angles to $m\angle 1$, $m\angle 2$, and $m\angle 3$ as per the problem's diagram or instructions. Since the problem states $m\angle 1 = $, $m\angle 2 = $, $m\angle 3 = $, and the given angles are four, it implies these three angles correspond to the given four angles. Assuming $m\angle 1 = 61$, $m\angle 2 = 88$, $m\angle 3 = 120$ and the missing angle is 76. ### Problem 6: Given angles: 33, 92, 115, 90 degrees. Step 1: Sum the known angles: $$33 + 92 + 115 + 90 = 330$$ Step 2: Find the missing angle: $$360 - 330 = 30$$ Step 3: Assign the missing angles similarly. Assuming $m\angle 1 = 33$, $m\angle 2 = 92$, $m\angle 3 = 115$, and the missing angle is 30. --- **Final answers:** - Problem 5: $m\angle 1 = 61^\circ$, $m\angle 2 = 88^\circ$, $m\angle 3 = 120^\circ$ - Problem 6: $m\angle 1 = 33^\circ$, $m\angle 2 = 92^\circ$, $m\angle 3 = 115^\circ$