1. **State the problem:** We have a larger rectangle made up of 14 small rectangles. Each small rectangle has a height of 12 mm. We need to find the area of the larger rectangle. 2. **Identify what is given and what is needed:** - Number of small rectangles: 14 - Height of each small rectangle: 12 mm - The arrangement is 3 rows: 5 rectangles in the first row, 5 in the second, and 4 in the third. 3. **Find the dimensions of the small rectangle:** - Height = 12 mm (given) - Width is unknown, but since the small rectangles are identical, the width is the same for all. 4. **Find the total height of the larger rectangle:** - The larger rectangle has 3 rows of small rectangles stacked vertically. - Total height = 3 \times 12 = $$36\text{ mm}$$ 5. **Find the total width of the larger rectangle:** - The widest row has 5 small rectangles side by side. - Let the width of one small rectangle be $$w$$. - Total width = $$5w$$ 6. **Find the area of the larger rectangle:** - Area = height \times width = $$36 \times 5w = 180w$$ 7. **Find the width $$w$$ of the small rectangle:** - Since the problem does not provide the width, we cannot find a numeric value for the area without it. **Conclusion:** - The area of the larger rectangle is $$180w$$ square millimeters, where $$w$$ is the width of one small rectangle. If the width of the small rectangle is provided, multiply it by 180 to get the area. **Note:** Without the width, the exact numeric area cannot be determined.