Rectangle Area Dd64D3

Let's solve the problem step by step! 🎉 1️⃣ Imagine you have a big rectangle that is 10 cm wide and 10 cm tall. 📏 2️⃣ Inside it, at the bottom left, there is a smaller rectangle 6 cm wide and 5 cm tall. 📐 3️⃣ To the right of the small rectangle, at the bottom, is a circle with a diameter of about 5 cm. 🔵 🔵🔵🔵🔵🔵 (diameter 5 cm) 4️⃣ Now, let's find the area of the big rectangle first: $$10 \times 10 = 100\text{ cm}^2$$ 5️⃣ Next, the area of the small rectangle: $$6 \times 5 = 30\text{ cm}^2$$ 6️⃣ The area of the circle is: $$\pi \times r^2$$ where radius $r$ is half the diameter, so $r = \frac{5}{2} = 2.5$ cm. $$\text{Area} = 3.14 \times 2.5^2 = 3.14 \times 6.25 = 19.625\text{ cm}^2$$ 7️⃣ Great! Now, the area left in the big rectangle that is NOT covered by the small rectangle or the circle is: $$100 - 30 - 19.625 = 50.375\text{ cm}^2$$ 🎯 Final answer: The leftover area is about $50.375$ square centimeters. Great job! Keep going! 🌟