1. **Problem statement:** We need to draw a rectangle in a Cartesian coordinate system with width 80 units and height 60 units. The top left corner of the rectangle is at coordinates $(20, 20)$.
2. **Understanding the rectangle's coordinates:**
- The top left corner is at $(20, 20)$.
- Since the width is 80 units, the top right corner will be at $(20 + 80, 20) = (100, 20)$.
- The height is 60 units, so the bottom left corner will be at $(20, 20 - 60) = (20, -40)$ because the y-coordinate decreases going down.
- The bottom right corner will be at $(100, -40)$.
3. **Summary of rectangle vertices:**
- Top left: $(20, 20)$
- Top right: $(100, 20)$
- Bottom left: $(20, -40)$
- Bottom right: $(100, -40)$
4. **Equation of rectangle sides:**
- Top side: $y = 20$ for $20 \leq x \leq 100$
- Bottom side: $y = -40$ for $20 \leq x \leq 100$
- Left side: $x = 20$ for $-40 \leq y \leq 20$
- Right side: $x = 100$ for $-40 \leq y \leq 20$
This fully specifies the rectangle in the Cartesian plane.
Rectangle Coordinates C2F1B0
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