1. **Problem 1: Rectangle ABCD with diagonal angle and side length**
Given: Rectangle ABCD with angle between diagonals $54^\circ$, side $CD = 19$ cm, find $x = AD$.
2. **Key properties:**
- In a rectangle, opposite sides are equal and all angles are $90^\circ$.
- Diagonals are equal in length.
- The diagonals intersect at an angle of $54^\circ$.
3. **Step 1: Define variables**
Let $AB = y$ cm (unknown), $BC = 19$ cm (given), $AD = y$ cm (since rectangle).
4. **Step 2: Length of diagonals**
Diagonal $AC = \sqrt{AB^2 + BC^2} = \sqrt{y^2 + 19^2}$.
Diagonal $BD = \sqrt{AB^2 + BC^2} = \sqrt{y^2 + 19^2}$ (equal).
5. **Step 3: Angle between diagonals**
The diagonals intersect at $54^\circ$. Using the formula for angle between two vectors:
$$\cos(54^\circ) = \frac{\vec{AC} \cdot \vec{BD}}{|AC||BD|}$$
6. **Step 4: Vector approach**
Set $A$ at origin $(0,0)$, $B$ at $(y,0)$, $C$ at $(y,19)$, $D$ at $(0,19)$.
Vectors:
$\vec{AC} = (y,19)$
$\vec{BD} = (0- y,19 - 0) = (-y,19)$
Dot product:
$$\vec{AC} \cdot \vec{BD} = y \times (-y) + 19 \times 19 = -y^2 + 361$$
Magnitude:
$$|AC| = \sqrt{y^2 + 19^2} = \sqrt{y^2 + 361}$$
$$|BD| = \sqrt{(-y)^2 + 19^2} = \sqrt{y^2 + 361}$$
7. **Step 5: Apply cosine formula**
$$\cos(54^\circ) = \frac{-y^2 + 361}{y^2 + 361}$$
8. **Step 6: Solve for $y$**
Let $c = \cos(54^\circ) \approx 0.5878$
$$c = \frac{-y^2 + 361}{y^2 + 361}$$
Multiply both sides:
$$c(y^2 + 361) = -y^2 + 361$$
$$cy^2 + 361c = -y^2 + 361$$
Bring terms to one side:
$$cy^2 + y^2 = 361 - 361c$$
$$y^2(c + 1) = 361(1 - c)$$
$$y^2 = \frac{361(1 - c)}{c + 1}$$
9. **Step 7: Calculate $y$**
$$y = \sqrt{\frac{361(1 - 0.5878)}{1 + 0.5878}} = \sqrt{\frac{361 \times 0.4122}{1.5878}} = \sqrt{93.7} \approx 9.68$$
10. **Step 8: Final answer**
Since $AD = y$,
$$x = AD \approx 9.68 \text{ cm}$$
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**Problem 2: Right-angled triangle ABC with angle bisector AD**
Given: Triangle ABC right angled at B, $AB = 29$ cm, angle bisector $AD$ of angle $BAC$, angle $DAC = 15^\circ$, find $x = CD$.
Since only the first problem is solved as per instructions, we do not solve this.
Rectangle Diagonal E2Fa38
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