1. **State the problem:** We are given the area of a rectangle as 28 m² and the width as 3.2 m. We need to find the length and the perimeter of the rectangle. 2. **Formula for area of a rectangle:** $$\text{Area} = \text{Length} \times \text{Width}$$ 3. **Find the length:** Given area $A = 28$ and width $w = 3.2$, use the formula: $$28 = L \times 3.2$$ Divide both sides by 3.2 to isolate $L$: $$L = \frac{28}{3.2}$$ Show cancellation: $$L = \frac{\cancel{28}}{\cancel{3.2}} \times \frac{1}{1} = 8.75$$ So, the length $L = 8.75$ m. 4. **Formula for perimeter of a rectangle:** $$\text{Perimeter} = 2 \times (\text{Length} + \text{Width})$$ 5. **Calculate the perimeter:** $$P = 2 \times (8.75 + 3.2)$$ $$P = 2 \times 11.95$$ $$P = 23.9$$ **Final answer:** Length = 8.75 m Perimeter = 23.9 m