1. **State the problem:** We have two rectangles, one inside the other. The outer rectangle has width 6 units and height 11 units. The inner rectangle is centered inside the outer one, and the frame (the shaded region) around the inner rectangle is 2 units wide. We need to find the area of this shaded frame. 2. **Understand the frame width:** The frame width of 2 units means the inner rectangle is smaller by 2 units on each side. So, the inner rectangle's width and height are reduced by twice the frame width (2 units on left + 2 units on right = 4 units total for width, similarly for height). 3. **Calculate inner rectangle dimensions:** - Inner width = Outer width $- 2 \times 2 = 6 - 4 = 2$ - Inner height = Outer height $- 2 \times 2 = 11 - 4 = 7$ 4. **Calculate areas:** - Area of outer rectangle = $6 \times 11 = 66$ - Area of inner rectangle = $2 \times 7 = 14$ 5. **Calculate shaded area (frame):** $$\text{Shaded area} = \text{Outer area} - \text{Inner area} = 66 - 14 = 52$$ 6. **Final answer:** The area of the shaded frame is $52$ square units.