1. **State the problem:** We are given a rectangle ABCD with vertices A(-7, 8), B(3, 8), C(-7, -6), and D(3, -6). We need to find: a) The perimeter of the rectangle. b) The area of the rectangle. 2. **Formula for perimeter of a rectangle:** $$\text{Perimeter} = 2(\text{length} + \text{width})$$ 3. **Formula for area of a rectangle:** $$\text{Area} = \text{length} \times \text{width}$$ 4. **Find the length and width:** Since the rectangle is aligned with the axes, the length and width can be found by the differences in x-coordinates and y-coordinates of the vertices. - Length (horizontal side) = distance between A and B or C and D: $$|x_B - x_A| = |3 - (-7)| = |3 + 7| = 10$$ - Width (vertical side) = distance between A and C or B and D: $$|y_A - y_C| = |8 - (-6)| = |8 + 6| = 14$$ 5. **Calculate the perimeter:** $$\text{Perimeter} = 2(10 + 14) = 2(24) = 48$$ 6. **Calculate the area:** $$\text{Area} = 10 \times 14 = 140$$ **Final answers:** - Perimeter = 48 - Area = 140