1. **State the problem:** We need to find the perimeter and area of a rectangle with vertices A(-6, 2), B(7, 2), C(-6, -8), and D(7, -8). 2. **Recall formulas:** - Perimeter of a rectangle: $$P = 2(\text{length} + \text{width})$$ - Area of a rectangle: $$A = \text{length} \times \text{width}$$ 3. **Find the length and width:** - Length is the horizontal distance between points A and B or C and D. $$\text{length} = |x_B - x_A| = |7 - (-6)| = |7 + 6| = 13$$ - Width is the vertical distance between points A and C or B and D. $$\text{width} = |y_A - y_C| = |2 - (-8)| = |2 + 8| = 10$$ 4. **Calculate the perimeter:** $$P = 2(13 + 10) = 2(23) = 46$$ 5. **Calculate the area:** $$A = 13 \times 10 = 130$$ **Final answers:** - Perimeter = 46 - Area = 130