1. **State the problem:** We need to find the perimeter and area of a rectangle with vertices at (5, -1), (5, -5), (-3, -5), and (-3, -1).
2. **Recall formulas:**
- Perimeter of a rectangle: $$P = 2(\text{length} + \text{width})$$
- Area of a rectangle: $$A = \text{length} \times \text{width}$$
3. **Find the length and width:**
- Length is the distance between points (5, -1) and (-3, -1) along the x-axis:
$$\text{length} = |5 - (-3)| = |5 + 3| = 8$$
- Width is the distance between points (5, -1) and (5, -5) along the y-axis:
$$\text{width} = |-1 - (-5)| = |-1 + 5| = 4$$
4. **Calculate the perimeter:**
$$P = 2(8 + 4) = 2(12) = 24$$
5. **Calculate the area:**
$$A = 8 \times 4 = 32$$
**Final answers:**
- Perimeter: 24 units
- Area: 32 square units
Rectangle Perimeter Area C46D23
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