1. **State the problem:** We have a rectangle ABCD with vertices A(-6,9), B(4,9), C(-6,-3), and D(4,-3). We need to find: a) The perimeter of the rectangle. b) The area of the rectangle. 2. **Recall formulas:** - Perimeter of a rectangle: $$P = 2(\text{length} + \text{width})$$ - Area of a rectangle: $$A = \text{length} \times \text{width}$$ 3. **Find the length and width:** Since the sides are parallel to the axes, length and width correspond to differences in x and y coordinates. - Length (horizontal side) = distance between points A and B (or C and D): $$\text{length} = |x_B - x_A| = |4 - (-6)| = |4 + 6| = 10$$ - Width (vertical side) = distance between points A and C (or B and D): $$\text{width} = |y_A - y_C| = |9 - (-3)| = |9 + 3| = 12$$ 4. **Calculate the perimeter:** $$P = 2(\text{length} + \text{width}) = 2(10 + 12) = 2 \times 22 = 44$$ 5. **Calculate the area:** $$A = \text{length} \times \text{width} = 10 \times 12 = 120$$ **Final answers:** - Perimeter = 44 - Area = 120