1. **Stating the problem:** We have two pieces, each a rectangle of dimensions 6 cm by 2 cm, and we want to arrange them to form a figure with a perimeter of 22 cm. 2. **Understanding the pieces:** Each piece is a rectangle with length $6$ cm and height $2$ cm. 3. **Possible arrangements:** - Placing the two rectangles side by side horizontally: total length $= 6 + 6 = 12$ cm, height $= 2$ cm. - Placing the two rectangles stacked vertically: length $= 6$ cm, height $= 2 + 2 = 4$ cm. 4. **Calculate perimeter for horizontal arrangement:** $$P = 2 \times (\text{length} + \text{height}) = 2 \times (12 + 2) = 2 \times 14 = 28 \text{ cm}$$ 5. **Calculate perimeter for vertical arrangement:** $$P = 2 \times (6 + 4) = 2 \times 10 = 20 \text{ cm}$$ 6. **Try to form a figure with perimeter 22 cm:** We need to find an arrangement where the perimeter is 22 cm. 7. **Consider arranging the two rectangles to form an L-shape:** - The total perimeter will be the sum of the outer edges. - The L-shape formed by joining one rectangle vertically and the other horizontally will have dimensions that can be calculated. 8. **Calculate perimeter of L-shape:** - The total width is $6 + 2 = 8$ cm (length of horizontal piece plus height of vertical piece). - The total height is $6$ cm (length of vertical piece). 9. **Perimeter of L-shape:** $$P = 2 \times (8 + 6) = 2 \times 14 = 28 \text{ cm}$$ 10. **Try another L-shape arrangement:** - Width $= 6$ cm - Height $= 2 + 2 = 4$ cm 11. **Perimeter:** $$P = 2 \times (6 + 4) = 20 \text{ cm}$$ 12. **Try overlapping one side to reduce perimeter:** - If the two rectangles share a side of length 2 cm, the perimeter reduces by $2 \times 2 = 4$ cm from 28 cm. - So, $28 - 4 = 24$ cm, still not 22 cm. 13. **Try overlapping a side of length 4 cm:** - Overlapping 4 cm side reduces perimeter by $2 \times 4 = 8$ cm. - So, $28 - 8 = 20$ cm. 14. **Try overlapping a side of length 3 cm:** - Overlapping 3 cm side reduces perimeter by $2 \times 3 = 6$ cm. - So, $28 - 6 = 22$ cm. 15. **Conclusion:** By arranging the two rectangles so that they overlap along a side of length 3 cm, the resulting figure has a perimeter of 22 cm. **Final answer:** Arrange the two pieces so that they overlap along a side of length 3 cm, forming a figure with perimeter $22$ cm.