Subjects geometry

Rectangle Width 33Cabc

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1. **State the problem:** We have a rectangle with a length of 210 inches and an area of 43 3/4 square feet. We need to find the width in inches. 2. **Convert the area to square inches:** Since 1 square foot = 144 square inches, convert 43 3/4 sq ft to sq in. $$43 \frac{3}{4} = 43.75$$ $$\text{Area in sq in} = 43.75 \times 144 = 6300$$ 3. **Use the area formula for a rectangle:** $$\text{Area} = \text{Length} \times \text{Width}$$ 4. **Substitute known values:** $$6300 = 210 \times \text{Width}$$ 5. **Solve for width:** $$\text{Width} = \frac{6300}{210} = 30$$ 6. **Answer:** The width is 30 inches.