1. **State the problem:** We need to find the width of a rectangular pyramid given its volume, height, and length. 2. **Formula for the volume of a rectangular pyramid:** $$V = \frac{1}{3} \times \text{length} \times \text{width} \times \text{height}$$ 3. **Convert all measurements to consistent units:** - Volume $V = 0.045$ m³ (already in meters cubed) - Height $h = 60$ cm = $0.6$ m - Length $l = 0.5$ m 4. **Rearrange the formula to solve for width $w$:** $$w = \frac{3V}{l \times h}$$ 5. **Substitute the known values:** $$w = \frac{3 \times 0.045}{0.5 \times 0.6}$$ 6. **Calculate the denominator:** $$0.5 \times 0.6 = 0.3$$ 7. **Calculate the numerator:** $$3 \times 0.045 = 0.135$$ 8. **Calculate the width:** $$w = \frac{0.135}{0.3} = 0.45$$ **Final answer:** The width of the rectangular pyramid is $0.45$ meters.