1. The problem asks for the coordinates of the reflection of vertex A across the line $x=6$. 2. The formula for reflecting a point $(x,y)$ across a vertical line $x = k$ is: $$x' = 2k - x, \quad y' = y$$ This means the reflected point has the same $y$-coordinate, and its $x$-coordinate is found by subtracting the original $x$ from twice the line of reflection. 3. Given vertex A at $(8,5)$ and the line of reflection $x=6$, apply the formula: $$x' = 2 \times 6 - 8 = 12 - 8 = 4$$ $$y' = 5$$ 4. Therefore, the reflected coordinates of vertex A are $(4,5)$. This reflection flips the point horizontally across the line $x=6$ while keeping the vertical position unchanged.