1. **State the problem:** We need to find the image of triangle \(\triangle STU\) after reflecting it over the x-axis. The original points are \(S(-4,-3)\), \(T(6,-3)\), and \(U(-4,-7)\). 2. **Reflection over the x-axis formula:** When a point \((x,y)\) is reflected over the x-axis, its image is \((x,-y)\). 3. **Apply the reflection to each vertex:** - For \(S(-4,-3)\), the image is \(S'(-4,-(-3)) = (-4,3)\). - For \(T(6,-3)\), the image is \(T'(6,-(-3)) = (6,3)\). - For \(U(-4,-7)\), the image is \(U'(-4,-(-7)) = (-4,7)\). 4. **Conclusion:** The reflected triangle \(\triangle S'T'U'\) has vertices \(S'(-4,3)\), \(T'(6,3)\), and \(U'(-4,7)\). This completes the reflection over the x-axis.