1. **State the problem:** We need to graph the image of rectangle KLMN after reflecting it over the y-axis. 2. **Recall the reflection rule:** When reflecting a point $(x,y)$ over the y-axis, the x-coordinate changes sign, so the image point is $(-x,y)$. 3. **Apply the reflection to each vertex:** - $K(3,3) \to K'(-3,3)$ - $L(6,3) \to L'(-6,3)$ - $M(6,8) \to M'(-6,8)$ - $N(3,8) \to N'(-3,8)$ 4. **Plot the original rectangle and its image:** The original rectangle is on the right side of the y-axis, and the reflected image is on the left side, symmetric about the y-axis. 5. **Final answer:** The reflected rectangle K'L'M'N' has vertices at $(-3,3)$, $(-6,3)$, $(-6,8)$, and $(-3,8)$.