1. The problem asks for the area of a rhombus-shaped window given the lengths of its diagonals. 2. The formula for the area of a rhombus is $$\text{Area} = \frac{1}{2} \times d_1 \times d_2$$ where $d_1$ and $d_2$ are the lengths of the diagonals. 3. From the problem, the diagonals are given as 28 cm and 35 cm (the other two 21 cm and 28 cm are likely sides or labels but the diagonals intersect at right angles, so we use the longest diagonals). 4. Substitute the values into the formula: $$\text{Area} = \frac{1}{2} \times 28 \times 35$$ 5. Calculate the product: $$28 \times 35 = 980$$ 6. Now multiply by $\frac{1}{2}$: $$\frac{1}{2} \times 980 = 490$$ 7. Therefore, the area of the rhombus-shaped window is **490 cm²**.