1. **State the problem:** We need to find the area of a rhombus with vertices at $(-3,0)$, $(0,2)$, $(3,0)$, and $(0,-2)$. 2. **Recall the formula for the area of a rhombus:** The area $A$ can be found using the lengths of the diagonals $d_1$ and $d_2$: $$A = \frac{1}{2} d_1 d_2$$ 3. **Find the lengths of the diagonals:** - The horizontal diagonal connects $(-3,0)$ to $(3,0)$, so its length is $$d_1 = 3 - (-3) = 6$$ - The vertical diagonal connects $(0,-2)$ to $(0,2)$, so its length is $$d_2 = 2 - (-2) = 4$$ 4. **Calculate the area:** $$A = \frac{1}{2} \times 6 \times 4 = \frac{1}{2} \times 24 = 12$$ 5. **Answer:** The area of the rhombus is $12$ square units.