1. **State the problem:** We need to find the image of rhombus BCDE after a 90° anticlockwise rotation around the origin.
2. **Recall the rotation formula:** For a point $(x,y)$, a 90° anticlockwise rotation about the origin transforms it to $(-y, x)$.
3. **Apply the rotation to each vertex:**
- For $B(-8,4)$: rotated to $B'(-4,-8)$
- For $C(-4,4)$: rotated to $C'(-4,-4)$
- For $D(0,6)$: rotated to $D'(-6,0)$
- For $E(-6,6)$: rotated to $E'(-6,-6)$
4. **Connect the rotated points in the same order:** $B'$, $C'$, $D'$, $E'$ to form the rotated rhombus.
5. **Summary:** The rotated rhombus has vertices at $B'(-4,-8)$, $C'(-4,-4)$, $D'(-6,0)$, and $E'(-6,-6)$.
This completes the rotation of rhombus BCDE by 90° anticlockwise about the origin.
Rhombus Rotation Cd5A98
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