1. **Problem:** Find the side length of a rhombus given its diagonals are 30 cm and 16 cm.
2. **Formula:** The diagonals of a rhombus bisect each other at right angles. Each side $s$ can be found using the Pythagorean theorem:
$$s = \sqrt{\left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2}$$
where $d_1$ and $d_2$ are the lengths of the diagonals.
3. **Calculation:**
- Half of diagonal 1: $\frac{30}{2} = 15$
- Half of diagonal 2: $\frac{16}{2} = 8$
4. Apply the formula:
$$s = \sqrt{15^2 + 8^2} = \sqrt{225 + 64} = \sqrt{289}$$
5. Simplify:
$$s = 17$$
6. **Answer:** The side length of the rhombus is **17 cm**.
Rhombus Side 41F7D1
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.