1. **State the problem:** We have a right isosceles triangle RST with right angle at T, sides RT = ST = 23 units, and base RS = t. We need to find the measures of angles \(\angle R\) and \(\angle S\).
2. **Recall properties:** In a right triangle, the sum of angles is 90° + 90° = 180°. Since \(\angle T = 90^\circ\), the other two angles \(\angle R\) and \(\angle S\) must sum to 90°.
3. **Isosceles right triangle:** Since RT = ST, the triangle is isosceles with legs equal, so \(\angle R = \angle S\).
4. **Calculate angles:** Let \(\angle R = \angle S = x\). Then:
$$x + x = 90^\circ$$
$$2x = 90^\circ$$
$$x = \frac{90^\circ}{2} = 45^\circ$$
5. **Final answer:**
$$m\angle R = 45^\circ$$
$$m\angle S = 45^\circ$$
Thus, both angles R and S measure 45 degrees each.
Right Triangle Angles D55C42
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