1. **Stating the problem:** Calculate the area ($a$) and perimeter ($p$) of the right triangle in the middle-right position with sides 6 cm, 8 cm, and hypotenuse 10 cm. 2. **Formula for right triangle area:** $$a = \frac{1}{2} \times \text{base} \times \text{height}$$ 3. **Formula for perimeter:** $$p = \text{sum of all sides}$$ 4. **Calculate area:** Base = 6 cm, Height = 8 cm $$a = \frac{1}{2} \times 6 \times 8 = \frac{1}{2} \times 48 = 24 \text{ cm}^2$$ 5. **Calculate perimeter:** $$p = 6 + 8 + 10 = 24 \text{ cm}$$ 6. **Final answers:** Area $a = 24$ cm² Perimeter $p = 24$ cm This uses the fact that the triangle is right angled, so the two legs are base and height, and the hypotenuse is the longest side.