1. **Problem statement:** Find the length of side $a$ in a right triangle where the hypotenuse is 6 and the angle opposite side $a$ is 60°.
2. **Formula used:** In a right triangle, the sine of an angle is the ratio of the length of the side opposite the angle to the hypotenuse:
$$\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$$
3. **Apply the formula:** Here, $\theta = 60^\circ$, opposite side is $a$, and hypotenuse is 6, so:
$$\sin(60^\circ) = \frac{a}{6}$$
4. **Solve for $a$:** Multiply both sides by 6:
$$a = 6 \times \sin(60^\circ)$$
5. **Calculate $\sin(60^\circ)$:**
$$\sin(60^\circ) = \frac{\sqrt{3}}{2} \approx 0.8660$$
6. **Substitute and compute:**
$$a = 6 \times 0.8660 = 5.196$$
7. **Round to the nearest hundredth:**
$$a \approx 5.20$$
**Final answer:** $a \approx 5.20$
Right Triangle Side 63Fcf2
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