1. **Problem:** In a right triangle, one shorter side is 6 units and the hypotenuse is 10 units. Find the length of the other shorter side. 2. **Formula:** Use the Pythagorean theorem: $$a^2 + b^2 = c^2$$ where $c$ is the hypotenuse. 3. **Apply values:** Let the unknown side be $b$, then: $$6^2 + b^2 = 10^2$$ 4. **Calculate squares:** $$36 + b^2 = 100$$ 5. **Isolate $b^2$:** $$b^2 = 100 - 36$$ $$b^2 = 64$$ 6. **Find $b$:** $$b = \sqrt{64} = 8$$ 7. **Answer:** The other shorter side is 8 units. **Final answer: A. 8 units**