Subjects geometry

Room Areas Ae0Ae6

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1. **Stating the problem:** Calculate the area of each room and the total area based on the given dimensions and shapes. 2. **Formula used:** The area of a rectangle is given by the formula $$\text{Area} = \text{length} \times \text{breadth}$$. 3. **Calculations:** - **Balcony:** Given dimensions are 6 m by 3 m. $$\text{Area} = 6 \times 3 = 18\, \text{m}^2$$ - **Kitchen:** Given dimensions are 10 m by 5 m. $$\text{Area} = 10 \times 5 = 50\, \text{m}^2$$ - **Dining Room:** Given dimensions are 16 m by 3 m. $$\text{Area} = 16 \times 3 = 48\, \text{m}^2$$ - **Toilet of Master Bedroom:** Given dimensions are 2 m by 3 m. $$\text{Area} = 2 \times 3 = 6\, \text{m}^2$$ - **Second Room:** Given dimensions are 3 m by 3 m. $$\text{Area} = 3 \times 3 = 9\, \text{m}^2$$ - **Movie Area:** Given dimensions are 5 m by 3 m. $$\text{Area} = 5 \times 3 = 15\, \text{m}^2$$ - **Entrance:** Given dimensions are 3 m by 3 m. $$\text{Area} = 3 \times 3 = 9\, \text{m}^2$$ 4. **Total Area:** Sum of all individual areas. $$\text{Total Area} = 18 + 50 + 48 + 6 + 9 + 15 + 9 = 155\, \text{m}^2$$ 5. **Explanation:** We multiply length and breadth for each room to find its area, then add all areas to get the total area. **Final answer:** - Balcony: $18\, \text{m}^2$ - Kitchen: $50\, \text{m}^2$ - Dining Room: $48\, \text{m}^2$ - Toilet of Master Bedroom: $6\, \text{m}^2$ - Second Room: $9\, \text{m}^2$ - Movie Area: $15\, \text{m}^2$ - Entrance: $9\, \text{m}^2$ - Total Area: $155\, \text{m}^2$