1. **State the problem:** We need to determine the maximum occupancy for each room based on the area and the occupancy limit of 1 person per 1.7 square meters. 2. **Calculate the area of each room:** - Room I is a quadrilateral with sides 26 m, 28 m, 16 m, and 16 m. We can split it into two triangles or use Brahmagupta's formula if it is cyclic. Since no angles are given, we approximate by splitting. - Room II is a rectangle with sides 20 m and 32 m. - Room III is a quadrilateral with sides 26 m, 36 m, and 16 m (incomplete info, assume similar approach as Room I). 3. **Room II area calculation:** $$\text{Area}_{II} = 20 \times 32 = 640 \text{ m}^2$$ 4. **Room I area calculation:** Assuming Room I is a trapezoid or can be split into two triangles. Using the formula for area of a quadrilateral with given sides is complex without angles, so approximate by splitting: Split into two triangles with sides (26,16,?) and (28,16,?). Without height, approximate area is given or use Heron's formula if height known. Since no height, assume approximate area is given or use average of sides times height (not provided). For this problem, let's assume the area is provided or use the occupancy limit to find max people. 5. **Room III area calculation:** Similarly, incomplete data for exact area calculation. 6. **Calculate maximum occupancy:** $$\text{Max Occupancy} = \frac{\text{Area}}{1.7}$$ 7. **Room II max occupancy:** $$\frac{640}{1.7} \approx 376 \text{ people}$$ 8. **Summary:** - Room II max occupancy is approximately 376 people. - Rooms I and III require more data (height or angles) for exact area calculation. **Note:** For precise answers, more geometric details are needed for Rooms I and III.