1. **State the problem:** We need to find the coordinates of the vertices of triangle RQS after a 180° counterclockwise rotation around the origin. 2. **Formula for rotation:** A 180° counterclockwise rotation around the origin transforms any point $(x,y)$ to $(-x,-y)$. 3. **Apply the formula to each vertex:** - For $R(-10,10)$, the new coordinates are $$(-(-10),-(10)) = (10,-10)$$ - For $Q(-10,3)$, the new coordinates are $$(-(-10),-(3)) = (10,-3)$$ - For $S(-5,1)$, the new coordinates are $$(-(-5),-(1)) = (5,-1)$$ 4. **Final answer:** The vertices after rotation are $R'(10,-10)$, $Q'(10,-3)$, and $S'(5,-1)$.