1. The problem asks how the pre-image triangle ABC was transformed to create the image triangle A'B'C'.
2. The transformation described is a 90° clockwise rotation around point C.
3. The formula for a 90° clockwise rotation of a point $(x,y)$ around a pivot point $(x_c,y_c)$ is:
$$
(x',y') = (x_c + (y - y_c), y_c - (x - x_c))
$$
This means each point is rotated such that the new coordinates are calculated relative to the pivot.
4. Applying this to points A and B around point C will map them to A' and B' respectively, confirming the rotation.
5. This transformation preserves distances from point C and rotates the figure 90° clockwise, matching the description and the graph.
Final answer: The pre-image ABC was transformed by a 90° clockwise rotation around point C to create image A'B'C'.
Rotation 90 Clockwise Fcab9C
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