1. **State the problem:** We need to find which two figures have the same area in square centimeters. 2. **Recall the area formulas:** - Trapezoid area: $$A = \frac{(b_1 + b_2)}{2} \times h$$ where $b_1$ and $b_2$ are the bases and $h$ is the height. - Rectangle area: $$A = l \times w$$ where $l$ is length and $w$ is width. - Triangle area: $$A = \frac{1}{2} \times b \times h$$ where $b$ is base and $h$ is height. - Square area: $$A = s^2$$ where $s$ is the side length. - Parallelogram area: $$A = b \times h$$ where $b$ is base and $h$ is height. 3. **Calculate each figure's area:** - Figure J (trapezoid): $$A_J = \frac{(4 + 12)}{2} \times 7 = \frac{16}{2} \times 7 = 8 \times 7 = 56$$ - Figure K (rectangle): $$A_K = 13 \times 4 = 52$$ - Figure L (triangle): $$A_L = \frac{1}{2} \times 7 \times 12 = \frac{1}{2} \times 84 = 42$$ - Figure M (square): $$A_M = 21^2 = 441$$ - Figure N (parallelogram): $$A_N = 6 \times 7 = 42$$ 4. **Compare areas:** - Figure J: 56 - Figure K: 52 - Figure L: 42 - Figure M: 441 - Figure N: 42 Figures L and N both have area 42 square centimeters. **Final answer:** Figures L and N have the same area.