1. The problem asks to find the point equidistant from three buildings located at points F, G, and H. 2. In geometry, the point equidistant from all vertices of a triangle is the circumcenter. 3. The circumcenter is found by the intersection of the perpendicular bisectors of the sides of the triangle. 4. The angle bisectors intersect at the incenter, which is equidistant from the sides, not the vertices. 5. Therefore, the correct point is where the perpendicular bisectors of FG, GH, and HF intersect. 6. This corresponds to option D. Final answer: D. the point where the perpendicular bisectors of FG, GH, and HF intersect