1. **State the problem:** We need to find the area of a sector of a circle with radius 5 cm and central angle 60°. 2. **Formula for the area of a sector:** The area $A$ of a sector with radius $r$ and central angle $\theta$ (in degrees) is given by: $$A = \frac{\theta}{360} \times \pi r^2$$ 3. **Substitute the known values:** Here, $r = 5$ cm and $\theta = 60^\circ$. $$A = \frac{60}{360} \times \pi \times 5^2$$ 4. **Simplify the fraction:** $$A = \frac{\cancel{60}}{\cancel{360}} \times \pi \times 25 = \frac{1}{6} \times \pi \times 25$$ 5. **Calculate the area:** $$A = \frac{25\pi}{6}$$ 6. **Approximate the value:** Using $\pi \approx 3.1416$, $$A \approx \frac{25 \times 3.1416}{6} = \frac{78.54}{6} = 13.09$$ 7. **Round to the nearest tenth:** $$A \approx 13.1 \text{ cm}^2$$ **Final answer:** The area of the blue shaded sector is approximately **13.1 cm²**.