1. **Problem statement:** We have two sectors OWX and OYZ with the same central angle of 75° but different radii: 39 cm and 28 cm respectively. We need to find the area of the shaded shape WXZY, which is the area between the two sectors. 2. **Formula for the area of a sector:** The area $A$ of a sector with radius $r$ and central angle $\theta$ (in degrees) is given by: $$A = \frac{\theta}{360} \times \pi r^2$$ 3. **Calculate the area of the larger sector OWX:** $$A_{OWX} = \frac{75}{360} \times \pi \times 39^2 = \frac{75}{360} \times \pi \times 1521$$ 4. **Calculate the area of the smaller sector OYZ:** $$A_{OYZ} = \frac{75}{360} \times \pi \times 28^2 = \frac{75}{360} \times \pi \times 784$$ 5. **Calculate the shaded area WXZY:** This is the difference between the two sector areas: $$A_{WXZY} = A_{OWX} - A_{OYZ} = \frac{75}{360} \times \pi (1521 - 784)$$ 6. **Simplify the difference inside the parentheses:** $$1521 - 784 = 737$$ 7. **Substitute and calculate:** $$A_{WXZY} = \frac{75}{360} \times \pi \times 737$$ 8. **Simplify the fraction:** $$\frac{75}{360} = \frac{\cancel{75}}{\cancel{360}} = \frac{5}{24}$$ 9. **Final calculation:** $$A_{WXZY} = \frac{5}{24} \times \pi \times 737 = \frac{5 \times 737}{24} \pi = \frac{3685}{24} \pi$$ 10. **Numerical value:** $$A_{WXZY} \approx \frac{3685}{24} \times 3.1416 \approx 483.0$$ **Answer:** The area of the shaded shape WXZY is approximately **483.0 cm²** to 1 decimal place.