1. **Stating the problem:** We have a figure composed of three smaller semicircles each with diameter $2$ m arranged side by side, and a larger semicircle enclosing them with diameter $6$ m. We need to find the perimeter of the shaded shape formed by these semicircles. 2. **Understanding the figure:** The three smaller semicircles face downward and are inside the larger semicircle which faces upward. The total width is $6$ m, so the larger semicircle has diameter $6$ m. 3. **Formula for circumference of a circle:** The circumference of a full circle is $C = \pi d$ where $d$ is the diameter. 4. **Calculate the perimeter parts:** - Each small semicircle has diameter $2$ m, so circumference of full circle is $\pi \times 2 = 2\pi$ m. - Each small semicircle perimeter (half circle) is $\frac{2\pi}{2} = \pi$ m. - There are 3 small semicircles, so total small semicircle perimeter is $3 \times \pi = 3\pi$ m. - The large semicircle has diameter $6$ m, so full circumference is $\pi \times 6 = 6\pi$ m. - Large semicircle perimeter (half circle) is $\frac{6\pi}{2} = 3\pi$ m. 5. **Determine the perimeter of the shaded shape:** - The shaded shape perimeter consists of the outer arc of the large semicircle (upward facing) plus the three lower arcs of the small semicircles (downward facing). - The straight lines along the diameters of the small semicircles are inside the figure and do not contribute to the perimeter. 6. **Add the arcs:** $$\text{Perimeter} = 3\pi + 3\pi = 6\pi$$ 7. **Final answer:** $$\boxed{6\pi \text{ meters}}$$ This is approximately $6 \times 3.1416 = 18.85$ meters. The perimeter of the shaded shape is $6\pi$ meters.