1. **Stating the problem:** We have a semicircle with diameter 28 cm. Inside it, two curved shapes meet at the top center, forming a shaded area enclosed by two arcs meeting at the top middle of the semicircle. We want to find the area of this shaded region. 2. **Formula and important rules:** The diameter $d$ of the semicircle is 28 cm, so the radius $r$ is $$r = \frac{d}{2} = \frac{28}{2} = 14 \text{ cm}.$$ The area of a full circle is $$A = \pi r^2,$$ so the area of the semicircle is half of that: $$A_{semicircle} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (14)^2 = 98\pi \text{ cm}^2.$$ 3. **Understanding the shaded area:** The shaded area is formed by two arcs inside the semicircle meeting at the top center. These arcs are likely parts of circles with radius equal to the semicircle's radius, intersecting at the top center. The shaded area is the lens-shaped region formed by these two arcs inside the semicircle. 4. **Calculating the shaded area:** The shaded area is the area of the semicircle minus the two identical segments outside the lens. Each segment corresponds to the area between the chord (the diameter) and the arc of the smaller circle. 5. **Using the formula for the area of a circular segment:** For a segment with radius $r$ and chord length $c$, the segment area is $$A_{segment} = r^2 \arccos\left(\frac{c}{2r}\right) - \frac{c}{2} \sqrt{4r^2 - c^2}.$$ 6. **Chord length:** The chord length $c$ is the diameter of the semicircle, 28 cm. 7. **Calculate the segment area:** Substitute $r=14$ and $c=28$: $$\arccos\left(\frac{28}{2 \times 14}\right) = \arccos(1) = 0,$$ so the segment area is zero, meaning the arcs coincide with the semicircle boundary. 8. **Conclusion:** The shaded area is the entire semicircle area: $$\boxed{98\pi \text{ cm}^2}.$$