1. **Problem statement:** Find the area of the shaded parts in a figure composed of two adjacent semicircles, each with radius 2 cm. The left semicircle is divided vertically into two halves, and the right semicircle is divided similarly. The shaded parts are the top-right quarter of the left semicircle and the bottom-left quarter of the right semicircle. 2. **Formula and rules:** - Area of a full circle: $$A = \pi r^2$$ - Area of a semicircle: $$\frac{1}{2} \pi r^2$$ - Since each semicircle is divided vertically into two halves, each quarter is $$\frac{1}{2}$$ of a semicircle. 3. **Calculate the area of one semicircle:** $$A_{semicircle} = \frac{1}{2} \pi (2)^2 = \frac{1}{2} \pi \times 4 = 2\pi$$ 4. **Calculate the area of one quarter (half of a semicircle):** $$A_{quarter} = \frac{1}{2} \times 2\pi = \cancel{\frac{1}{2}} \times \cancel{2}\pi = \pi$$ 5. **Calculate total shaded area:** There are two shaded quarters, so total shaded area is: $$A_{shaded} = 2 \times \pi = 2\pi$$ 6. **Numerical value:** $$2\pi \approx 2 \times 3.1416 = 6.2832$$ Rounded to one decimal place: $$6.3$$ cm² **Final answer:** The area of the shaded parts is **6.3 cm²**.