1. **Problem:** Find the area of the shaded trapezoid with a smaller quadrilateral cutout inside. 2. **Formula:** Area of trapezoid = $$\frac{1}{2} (b_1 + b_2) h$$ where $b_1$ and $b_2$ are the parallel sides and $h$ is the height. 3. **Outer trapezoid:** Bases are 15 ft and 25 ft, height is 20 ft. $$\text{Area}_{outer} = \frac{1}{2} (15 + 25) \times 20 = \frac{1}{2} \times 40 \times 20 = 400 \text{ ft}^2$$ 4. **Inner quadrilateral cutout:** Approximated as a rectangle with sides 8 ft and 12 ft. $$\text{Area}_{inner} = 8 \times 12 = 96 \text{ ft}^2$$ 5. **Shaded area:** $$\text{Area}_{shaded} = \text{Area}_{outer} - \text{Area}_{inner} = 400 - 96 = 304 \text{ ft}^2$$ **Final answer:** The area of the shaded region is **304 ft\textsuperscript{2}**.